Matematika Sekolah Menengah Atas 1). Lim ( x^x + x! - 7x - 5 )
x = 2

2). 7(8) + 2(9) - 3(0) = ..​

By di
1). Lim ( x^x + x! - 7x - 5 ) x = 2 2). 7(8) + 2(9) - 3(0) = ..​ Lim(x^x + x! - 7x - 5) x = 2 = 2² + 2! - 7(2) - 5 = (2 × 2) + (2 × 1) - (7 × 2) - 5 = 4 + 2 - 14 - 5 = 6 - 19 => - 13 . 7(8) + 2(9) - 3(0) = (7 × 8) + (2 × 9) - (3 × 0) = 56 + 18 - 0 = 74 - 0 => 74 #CMIIW [tex] \colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}[/tex] [tex]{ \pink{ \underline{ \purple{ \underline {\mathfrak\color{red}{Riiax}}}}}}[/tex] Jawaban: Lim ( x^x + x! - 7x - 5) x => 2 penyelesaian : 2^2 + 2! - 7(2) - 5 (2 × 2) + (2 × 1) - 14 - 5 4 + 2 - 14 - 5 6 - 14 - 5 -8 - 5 = - 1 3 7 ( 8 ) + 2(9) - 3(0) 56 + 18 - 0 74 - 0 = 74